_tkinter.TclError: invalid command name “.!canvas”

In python _tkinter.TclError: invalid command name “.!canvas” we face this error message when we type an incorrect turtle.done() or related argument in starting then the python interpreter shows this error message, If you want to fix this error you need to just remove turtle.done() or related argument and type end of your code, For more clarification, see the below example.

Wrong Code

import turtle
t = turtle.Turtle()
turtle.done()

# set the turtle's pen size
t.pensize(3)

# set the number of steps for the loop
steps = 20

# initialize a variable to keep track of the current step
current_step = 0

# move the turtle forward and leave a mark
t.pendown()
while current_step < steps:
    t.forward(5)
    t.penup()
    t.forward(5)
    current_step += 1

Error Massage

Traceback (most recent call last):
  File "/home/kali/python/webproject/error/main.py", line 41, in <module>
    t.pensize(3)
  File "/usr/lib/python3.10/turtle.py", line 2092, in pensize
    self.pen(pensize=width)
  File "/usr/lib/python3.10/turtle.py", line 2425, in pen
    self._newLine()
  File "/usr/lib/python3.10/turtle.py", line 3292, in _newLine
    self.screen._drawline(self.currentLineItem, top=True)
  File "/usr/lib/python3.10/turtle.py", line 550, in _drawline
    self.cv.tag_raise(lineitem)
  File "<string>", line 1, in tag_raise
  File "/usr/lib/python3.10/tkinter/__init__.py", line 2971, in tag_raise
    self.tk.call((self._w, 'raise') + args)
_tkinter.TclError: invalid command name ".!canvas"

Wrong code line

1 import turtle
2 t = turtle.Turtle()
3 turtle.done()

Correct code line

57 turtle.done()

• Improper action: starting turtle.done().
• Correct action: end of the code.

Entire Correct Code line

mport turtle
t = turtle.Turtle()

# set the turtle's pen size
t.pensize(3)

# set the number of steps for the loop
steps = 20

# initialize a variable to keep track of the current step
current_step = 0

# move the turtle forward and leave a mark
t.pendown()
while current_step < steps:
    t.forward(5)
    t.penup()
    t.forward(5)
    current_step += 1

turtle.done()

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